Maestro n° 094 : Page 82 - Gr 79

L’Approche du tigre (AIC type I)

L6C3 =5= L8C3 -5-1- L8C3 =1= L8C1 -1- L2C1 =1=2= L2C1 -2- L5C1 =2=6= L5C1 -6- L5C3 =6= L9C3 -6- L9C7 =6= L1C7 -6-5- L1C7 =5= L1C9 -5- L7C9 =5= L7C1 donc L6C1 et L8C3 ≠ 5