Suprême n° 028 : Page 16 - Gr 13

L’Approche du tigre (AIC type I)

L1C6 =8= L1C2 -8-2- L1C2 =2= L1C8 -2- L6C8 =2=8= L6C8 -8- L6C7 =8= L7C7 -8- L7C1 =8= L2C1 donc L1C2 et L2C6 ≠ 8