Suprême n° 034 : Page 32 - Gr 29

L’Approche du tigre (AIC type I)

L1C1 =2= L5C1 -2- L6C2 =2=5= L6C2 -5- L6C4 =5=6= L6C4 -6- L6C8 =6= L5C8 -6-1- L5C8 =1= L4C8 -1-4- L4C8 =4= L5C7 -4- L3C7 =4=8= L3C7 -8- L3C8 =8=2= L3C8 donc L1C89 et L3C2 ≠ 2