Suprême n° 034 : Page 50 - Gr 47

L’Approche du tigre (AIC type I)

L4C3 =5= L4C8 -5-8- L4C8 =8= L2C8 -8-1- L2C8 =1= L3C8 -1-7- L3C8 =7= L7C8 -7- L7C3 =7=3= L7C3 -3- L9C3 =3= L9C5 -3- L5C5 =3=8= L5C5 -8- L5C1 =8= L6C1 -8-5- L6C1 =5= L9C1 donc L6C1 et L9C3 ≠ 5